19 Dec 69. Sqrt(x)
Posted at 20:55h in Coding 0 Comments
Given a non-negative integer
x, return the square root of
x rounded down to the nearest integer. The returned integer should be non-negative as well.
You must not use any built-in exponent function or operator.
- For example, do not use
pow(x, 0.5)in c++ or
x ** 0.5in python.
Input: x = 4 Output: 2 Explanation: The square root of 4 is 2, so we return 2.
Input: x = 8 Output: 2 Explanation: The square root of 8 is 2.82842..., and since we round it down to the nearest integer, 2 is returned.
def mySqrt(self, x: int) -> int:
left = 0
right = x
while left <= right:
middle = left+(right – left) //2
if middle * middle == x:
elif x > middle * middle:
left = middle +1
right = middle -1
return left – 1