19 Dec 69. Sqrt(x)
Given a non-negative integer x, return the square root of x rounded down to the nearest integer. The returned integer should be non-negative as well.
You must not use any built-in exponent function or operator.
- For example, do not use
pow(x, 0.5)in c++ orx ** 0.5in python.
Example 1:
Input: x = 4 Output: 2 Explanation: The square root of 4 is 2, so we return 2.
Example 2:
Input: x = 8 Output: 2 Explanation: The square root of 8 is 2.82842..., and since we round it down to the nearest integer, 2 is returned.
class Solution:
def mySqrt(self, x: int) -> int:
left = 0
right = x
while left <= right:
middle = left+(right – left) //2
print(middle)
if middle * middle == x:
return middle
elif x > middle * middle:
left = middle +1
else:
right = middle -1
print(“————“)
return left – 1
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